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Sentinel: Descendants in Time Hints
How do I figure out the correct solution?
1 of 12: Remember that all stands will need to be used, but none of the lights can be activated more or less than three times.
2 of 12: For each stand there will be a set of lights that will be activated and a set that will not be activated. When comparing the sets of lights between two stands, the sets of unactivated lights must be different for each stand, otherwise it will be impossible to get all the lights activated exactly three times each.
3 of 12: If, at any time in testing a switch from one stand (call this switch "A"), all the switches from a different stand cannot be combined with switch "A" (because some of the same lights will be deactivated), then switch "A" would need to be eliminated as a possible choice.
4 of 12: Start by looking at the switches of one stand, one at a time, and eliminating one switch at a time until you find the correct switch combination.
5 of 12: Starting with your notes for the first switch on the first stand, go through all the possibilities for the switches on the second stand (one switch at a time), to see whether or not any of the unactivated lights are the same as the ones for the first switch.
6 of 12: If two switches would leave the same lights deactivated, then they are not a possible combination. Make note of any combinations with switches on the second stand that are possibilities with the first switch of the first stand.
7 of 12: If there aren't any possible combinations on the second stand, then the first switch on the first stand would not be a possible choice. You could eliminate the first switch (from the first stand) from further testing and go on to the second switch (of the first stand).
8 of 12: If, however, there was a possible combination between the first switch and with one (or more) switch(es) on the second stand, then the switches on the third stand would also need to be tested (with every possible combination from the first two stands) to see if there were any switches on the third stand that did not leave the same lights deactivated.
9 of 12: If all of the switches from the third stand kept the same lights deactivated in the combination you are testing, then that combination of switches would not be a possible choice. If all combinations from the first switch (from the first stand) are eliminated, then you can eliminate the first switch as a possibility and move onto the next switch (from the first stand).
10 of 12: If, however, you now have one or more possible combinations of three switches (one from each stand) that do not leave the same lights deactivated, then you will need to move on to the final stand to test those switches for possible combinations.
11 of 12: If you find that all of the switches on the fourth stand leave more than one light deactivated in any of your possible combinations, then you can eliminate those combinations, and (finally) eliminate the switch from the first stand that you were testing. At this point, you can start testing the next switch on the first stand, going through the possibilities, as you did for the first switch)
12 of 12: If, however, you a combination of four switches (one from each stand) that works (where each light is activated exactly three times) you have found your final answer to this puzzle.
